{
  "contentStorage": "postgres",
  "title": "纳克尔星人 · Versionen",
  "description": "纳克尔星人是《归来的奥特曼》后半登场的暗杀型宇宙人，以研究奥特曼战斗数据并设局作战著称。",
  "url": "/de/people/alien-nackle/versions.html",
  "entity": {
    "id": "person_alien_nackle",
    "type": "person",
    "title": "纳克尔星人",
    "slug": "alien-nackle",
    "aliases": [
      "ナックル星人",
      "Alien Nackle"
    ],
    "summary": "纳克尔星人是《归来的奥特曼》后半登场的暗杀型宇宙人，以研究奥特曼战斗数据并设局作战著称。",
    "status": "published",
    "categories": [
      "category-people",
      "category-fictional-characters"
    ],
    "tags": [
      "tag-character-ip",
      "tag-ultraman"
    ],
    "sources": [
      {
        "id": "s1",
        "title": "キャラクター（角色一览）",
        "author": "圆谷制作（円谷ステーション）",
        "url": "https://m-78.jp/character/",
        "locator": "ナックル星人：初登場年度、登場作品"
      }
    ],
    "createdAt": "2026-10-31T12:00:00+08:00",
    "updatedAt": "2026-10-31T10:23:35+08:00",
    "updatedBy": "user:admin",
    "revision": 1,
    "body": "纳克尔星人（ナックル星人）是 1971 年《[[work_return_of_ultraman|归来的奥特曼]]》后半登场的宇宙人。\n\n## 设定\n\n他仔细研究 [[person_ultraman_jack|杰克·奥特曼]] 的战斗方式并制定暗杀计划，驱使怪兽与杀手并肩作战，是系列早期「以策略对抗英雄」的代表敌役。\n\n## 影响\n\n纳克尔星人在新生代作品与群像企划中多次回归，其「研究对手」的战斗方式被后来的敌役沿用。",
    "url": "/people/alien-nackle.html",
    "lang": "de",
    "fallback": true,
    "availableLangs": [
      "zh"
    ],
    "occupations": [
      "宇宙人（敌役）"
    ],
    "disambiguation": "《归来的奥特曼》中的暗杀宇宙人",
    "isFictional": true
  },
  "entities": null,
  "versions": [
    {
      "revision": 1,
      "updatedAt": "2026-10-31T10:23:35+08:00",
      "message": "当前版本",
      "hasSnapshot": true,
      "url": "/de/people/alien-nackle/at/1.html"
    }
  ],
  "lang": "de",
  "availableLangs": [
    "zh"
  ],
  "fallback": true,
  "infoFields": [
    {
      "key": "is_fictional",
      "label": "Fictional",
      "value": "yes"
    },
    {
      "key": "occupations",
      "label": "Occupations",
      "value": "宇宙人（敌役）"
    },
    {
      "key": "disambiguation",
      "label": "Disambiguation",
      "value": "《归来的奥特曼》中的暗杀宇宙人"
    }
  ],
  "pagination": {
    "page": 1,
    "pageSize": 50,
    "total": 1,
    "pageCount": 1
  }
}