{
  "contentStorage": "postgres",
  "title": "德凯·奥特曼 · Versioni",
  "description": "德凯·奥特曼是 2022 年《德凯·奥特曼》的主角，人间体为明日见奏大，拥有闪亮型、强壮型、奇迹型与强劲型形态。",
  "url": "/it/people/ultraman-decker/versions.html",
  "entity": {
    "id": "person_ultraman_decker",
    "type": "person",
    "title": "德凯·奥特曼",
    "slug": "ultraman-decker",
    "aliases": [
      "ウルトラマンデッカー",
      "Ultraman Decker"
    ],
    "summary": "德凯·奥特曼是 2022 年《德凯·奥特曼》的主角，人间体为明日见奏大，拥有闪亮型、强壮型、奇迹型与强劲型形态。",
    "status": "published",
    "categories": [
      "category-people",
      "category-fictional-characters"
    ],
    "tags": [
      "tag-character-ip",
      "tag-ultraman"
    ],
    "sources": [
      {
        "id": "s1",
        "title": "キャラクター（角色一览）",
        "author": "圆谷制作（円谷ステーション）",
        "url": "https://m-78.jp/character/",
        "locator": "ウルトラマンデッカー：初登場年度、登場作品、タイプチェンジ"
      }
    ],
    "createdAt": "2026-10-31T12:00:00+08:00",
    "updatedAt": "2026-10-31T00:40:56+08:00",
    "updatedBy": "user:admin",
    "revision": 1,
    "body": "德凯·奥特曼（ウルトラマンデッカー）是 2022 年作品《德凯·奥特曼》的主角，舞台为特利迦时代之后的世界。\n\n## 设定\n\n他由 GUTS-SELECT 新队员明日见奏大变身，可在闪亮型、强壮型、奇迹型与强劲型之间切换形态。\n\n## 特点\n\n作品延续「超古代巨人」主线，并让前作角色特利迦·奥特曼继续登场，构成连续的令和世界观。",
    "url": "/people/ultraman-decker.html",
    "lang": "it",
    "fallback": true,
    "availableLangs": [
      "zh"
    ],
    "occupations": [
      "奥特战士"
    ],
    "disambiguation": "2022 年《德凯·奥特曼》主角",
    "isFictional": true
  },
  "entities": null,
  "versions": [
    {
      "revision": 1,
      "updatedAt": "2026-10-31T00:40:56+08:00",
      "message": "当前版本",
      "hasSnapshot": true,
      "url": "/it/people/ultraman-decker/at/1.html"
    }
  ],
  "lang": "it",
  "availableLangs": [
    "zh"
  ],
  "fallback": true,
  "infoFields": [
    {
      "key": "is_fictional",
      "label": "Fictional",
      "value": "yes"
    },
    {
      "key": "occupations",
      "label": "Occupations",
      "value": "奥特战士"
    },
    {
      "key": "disambiguation",
      "label": "Disambiguation",
      "value": "2022 年《德凯·奥特曼》主角"
    }
  ],
  "pagination": {
    "page": 1,
    "pageSize": 50,
    "total": 1,
    "pageCount": 1
  }
}