{
  "contentStorage": "postgres",
  "title": "大耳狗",
  "description": "大耳狗（Cinnamoroll）是三丽鸥 2001 年推出的角色，官方设定为出生于云端之上的小狗男孩 Cinnamon，以大耳朵飞行，尾巴形似肉桂卷，官方生日为 3 月 6 日。",
  "url": "/ms/people/cinnamoroll.html",
  "entity": {
    "id": "person_cinnamoroll",
    "type": "person",
    "title": "大耳狗",
    "slug": "cinnamoroll",
    "aliases": [
      "Cinnamoroll",
      "玉桂狗",
      "肉桂狗",
      "シナモロール",
      "Cinnamon",
      "大耳狗喜拿"
    ],
    "summary": "大耳狗（Cinnamoroll）是三丽鸥 2001 年推出的角色，官方设定为出生于云端之上的小狗男孩 Cinnamon，以大耳朵飞行，尾巴形似肉桂卷，官方生日为 3 月 6 日。",
    "status": "published",
    "categories": [
      "category-acg",
      "category-fictional-characters"
    ],
    "tags": [
      "tag-sanrio",
      "tag-character-ip"
    ],
    "sources": [
      {
        "id": "s1",
        "title": "Characters",
        "author": "Sanrio SEA（Sanrio Co., Ltd.）",
        "url": "https://sanrio-sea.com/characters"
      },
      {
        "id": "s2",
        "title": "2025年サンリオキャラクター大賞 結果発表（総合順位）",
        "author": "株式会社サンリオ",
        "date": "2025-06-29",
        "url": "https://www.sanrio.co.jp/special/characterranking/2025/result/"
      }
    ],
    "createdAt": "2026-10-30T00:00:00+08:00",
    "updatedAt": "2026-10-31T00:09:34+08:00",
    "updatedBy": "user:admin",
    "revision": 2,
    "body": "大耳狗（Cinnamoroll，日文：シナモロール）是三丽鸥于 2001 年 9 月推出的角色，官方姓名为 Cinnamon，设定为出生在遥远云端之上的小狗男孩：一对大耳朵可以扇动飞行，卷曲的尾巴形似肉桂卷。性格安静但亲人，常在客人膝上睡着。官方设定的生日为 3 月 6 日。\n\n大耳狗在三丽鸥角色人气投票中长期位居前列，2025 年 6 月公布的第 40 届「三丽鸥角色大赏」中以 5,427,983 票获得总排名第二。\n\n参见：[[organization_sanrio|三丽鸥]]、[[person_pompompurin|布丁狗]]",
    "url": "/people/cinnamoroll.html",
    "lang": "ms",
    "fallback": true,
    "availableLangs": [
      "zh"
    ],
    "disambiguation": "三丽鸥角色",
    "isFictional": true,
    "personCategory": "三丽鸥角色"
  },
  "entities": null,
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    {
      "id": "tag-sanrio",
      "slug": "sanrio",
      "name": "Sanrio",
      "description": "Sanrio characters, products, collaborations and group companies.",
      "names": {
        "en": "Sanrio",
        "ja": "サンリオ",
        "ko": "산리오",
        "zh": "三丽鸥",
        "zh-hant": "三麗鷗"
      },
      "descriptions": {
        "en": "Sanrio characters, products, collaborations and group companies.",
        "zh": "三丽鸥角色、商品、联名与企业相关的条目。"
      },
      "count": 29
    },
    {
      "id": "tag-character-ip",
      "slug": "character-ip",
      "name": "IP watak",
      "description": "Character-based IP with its licensing, merchandise and brand collaborations.",
      "names": {
        "ar": "ملكية شخصية",
        "de": "Figuren-IP",
        "en": "Character IP",
        "es": "IP de personaje",
        "fr": "IP de personnage",
        "hi": "कैरेक्टर आईपी",
        "id": "IP karakter",
        "it": "IP del personaggio",
        "ja": "キャラクターIP",
        "ko": "캐릭터 IP",
        "ms": "IP watak",
        "nl": "Personage-IP",
        "pt": "IP de personagem",
        "ru": "Персонажный IP",
        "th": "ไอพีตัวละคร",
        "tr": "Karakter IP",
        "vi": "IP nhân vật",
        "zh": "角色 IP",
        "zh-hant": "角色 IP"
      },
      "descriptions": {
        "en": "Character-based IP with its licensing, merchandise and brand collaborations.",
        "zh": "以角色形象为核心的 IP 及其授权、周边与联名。"
      },
      "count": 180
    }
  ],
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      "toId": "organization_sanrio",
      "role": "旗下角色",
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        {
          "entityId": "person_cinnamoroll",
          "sourceId": "s1"
        }
      ],
      "label": "Member of",
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      "targetTitle": "Sanrio",
      "targetUrl": "/ms/organizations/sanrio.html",
      "incoming": false
    },
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      "fromId": "concept_sanrio_characters",
      "relationType": "exemplified_by",
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      "sourceRefs": [
        {
          "entityId": "concept_sanrio_characters",
          "sourceId": "s1"
        }
      ],
      "label": "Exemplifies concepts",
      "targetId": "concept_sanrio_characters",
      "targetTitle": "三丽鸥角色",
      "targetUrl": "/ms/concepts/sanrio-characters.html",
      "incoming": true
    },
    {
      "id": "relation_api_e27c5ff1f4745ee77019e05e",
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      "relationType": "depicts",
      "toId": "person_cinnamoroll",
      "sourceRefs": [
        {
          "entityId": "work_uniqlo_ut_hello_kitty_50th_2024",
          "sourceId": "s1"
        }
      ],
      "label": "Related works",
      "targetId": "work_uniqlo_ut_hello_kitty_50th_2024",
      "targetTitle": "UNIQLO UT「Hello Kitty 50周年」",
      "targetUrl": "/ms/works/uniqlo-ut-hello-kitty-50th-2024.html",
      "incoming": true
    }
  ],
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      "fromTitle": "三丽鸥角色",
      "fromUrl": "/ms/concepts/sanrio-characters.html",
      "fromType": "concept"
    },
    {
      "fromId": "organization_sanrio",
      "fromTitle": "Sanrio",
      "fromUrl": "/ms/organizations/sanrio.html",
      "fromType": "organization"
    },
    {
      "fromId": "person_pompompurin",
      "fromTitle": "布丁狗",
      "fromUrl": "/ms/people/pompompurin.html",
      "fromType": "person"
    }
  ],
  "versions": [
    {
      "revision": 2,
      "updatedAt": "2026-10-31T00:09:34+08:00",
      "message": "当前版本",
      "hasSnapshot": true,
      "url": "/ms/people/cinnamoroll/at/2.html"
    }
  ],
  "lang": "ms",
  "availableLangs": [
    "zh"
  ],
  "fallback": true,
  "infoFields": [
    {
      "key": "is_fictional",
      "label": "Fictional",
      "value": "yes"
    },
    {
      "key": "person_category",
      "label": "Person category",
      "value": "三丽鸥角色"
    },
    {
      "key": "disambiguation",
      "label": "Disambiguation",
      "value": "三丽鸥角色"
    }
  ],
  "relationsTotal": 3,
  "relationCounts": [
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      "incoming": false,
      "label": "Member of",
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    },
    {
      "relationType": "exemplified_by",
      "incoming": true,
      "label": "Exemplifies concepts",
      "total": 1
    },
    {
      "relationType": "depicts",
      "incoming": true,
      "label": "Related works",
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    }
  ],
  "mentionsTotal": 3,
  "rankings": [
    {
      "listId": "work_sanrio_character_ranking_2025",
      "listTitle": "2025年三丽鸥角色大赏",
      "listUrl": "/ms/works/sanrio-character-ranking-2025.html",
      "edition": "2025年6月29日",
      "name": "大耳狗",
      "rank": 2
    }
  ],
  "rankingsTotal": 1
}